The Washington State Journeyman Electrician exam is one of the most challenging in the country, requiring 8,000 verified hours of supervised electrical work and 96 hours of classroom instruction before you’re even eligible. Candidates with military training or out-of-state licenses may also qualify, provided they meet Washington’s work-hour and documentation requirements. Passing the exam earns your state-issued Journeyman Electrician Certificate, an essential step for advancing your electrical career.
The exam is divided into two parts: 60 questions on the National Electrical Code® (NEC) and electrical theory (3 hours) and 17 questions on Washington State laws and rules (1 hour). To succeed, you must score at least 70% overall. Expect questions on grounding, wiring methods, conductor sizing, overcurrent protection, motors, special occupancies, and local RCW 19.28 and WAC 296-46B requirements. Because the test combines national code with Washington-specific regulations, being able to navigate both references quickly is key.
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The correct answer is
NEC 2017: Table 110.28NEC 2020: Table 110.28NEC 2023: Table 110.28
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NEC 2017: Table 110.28NEC 2020: Table 110.28NEC 2023: Table 110.28
The correct answer is
Step 1: For a 150-volt range, the same 0.01 amps must flow.150 volts divided by 0.01 amps = 15,000 ohms total resistance required.
Step 2: The meter already has 300 ohms inside it.So the extra series resistor needed is 15,000 minus 300 = 14,700 ohms.
Answer: 14.7 kilo-ohms in series.
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Step 1: For a 150-volt range, the same 0.01 amps must flow.150 volts divided by 0.01 amps = 15,000 ohms total resistance required.
Step 2: The meter already has 300 ohms inside it.So the extra series resistor needed is 15,000 minus 300 = 14,700 ohms.
Answer: 14.7 kilo-ohms in series.
The correct answer is
NEC 2017: Table 430.250, 430.52(C)(1), 430.52(C)(1)(a)(2), 240.6NEC 2020: Table 430.250, 430.52(C)(1), 430.52(C)(1)(a)(2), 240.6NEC 2023: Table 430.250, 430.52(C)(1), 430.52(C)(1)(a)(2), 240.6Step 1: Find the FLC for a 20 hp, 208-volt, three-phase Design B motor in Table 430.250. The FLC is 59.4 amperes. Step 2: Calculate 225% of FLC: 59.4 × 225% = 133.65 amperes. Step 3: The next lower standard fuse size is 125 amperes, which doesn't exceed 225% of FLC. Step 4: Therefore, the maximum permitted fuse rating is 125 amperes.
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NEC 2017: Table 430.250, 430.52(C)(1), 430.52(C)(1)(a)(2), 240.6NEC 2020: Table 430.250, 430.52(C)(1), 430.52(C)(1)(a)(2), 240.6NEC 2023: Table 430.250, 430.52(C)(1), 430.52(C)(1)(a)(2), 240.6Step 1: Find the FLC for a 20 hp, 208-volt, three-phase Design B motor in Table 430.250. The FLC is 59.4 amperes. Step 2: Calculate 225% of FLC: 59.4 × 225% = 133.65 amperes. Step 3: The next lower standard fuse size is 125 amperes, which doesn't exceed 225% of FLC. Step 4: Therefore, the maximum permitted fuse rating is 125 amperes.
The correct answer is
NEC 2017: Table 250.66, 250.66(B)
NEC 2020: Table 250.66, 250.66(B)
NEC 2023: Table 250.66, 250.66(B)
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NEC 2017: Table 250.66, 250.66(B)
NEC 2020: Table 250.66, 250.66(B)
NEC 2023: Table 250.66, 250.66(B)
The correct answer is
NEC 2017: 310.15(B)(7), Table 310.15(B)(16), Annex D Example D7NEC 2020: 310.12(A), Table 310.12NEC 2023: 310.12(A), Table 310.12
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NEC 2017: 310.15(B)(7), Table 310.15(B)(16), Annex D Example D7NEC 2020: 310.12(A), Table 310.12NEC 2023: 310.12(A), Table 310.12
The correct answer is
NEC 2017: 517.19(B)(1) and (2)NEC 2020: 517.19(B)(1) and (2)NEC 2023: 517.19(B)(1) and (2)
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NEC 2017: 517.19(B)(1) and (2)NEC 2020: 517.19(B)(1) and (2)NEC 2023: 517.19(B)(1) and (2)
The correct answer is
NEC 2017: 210.12(A)NEC 2020: 210.12(A)NEC 2023: 210.12(A)
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NEC 2017: 210.12(A)NEC 2020: 210.12(A)NEC 2023: 210.12(A)
The correct answer is
NEC 2017: Table 110.26(A)(1), Condition 2NEC 2020: Table 110.26(A)(1), Condition 2NEC 2023: Table 110.26(A)(1), Condition 2
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NEC 2017: Table 110.26(A)(1), Condition 2NEC 2020: Table 110.26(A)(1), Condition 2NEC 2023: Table 110.26(A)(1), Condition 2